1/9=27^2x+1

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Solution for 1/9=27^2x+1 equation: 



1/9=27^2x+1

We move all terms to the left:

1/9-(27^2x+1)=0

We get rid of parentheses

-27^2x-1+1/9=0

We multiply all the terms by the denominator


-27^2x*9+1-1*9=0

We add all the numbers together, and all the variables

-27^2x*9-8=0

Wy multiply elements

-243x^2-8=0

a = -243; b = 0; c = -8;
Δ = b2-4ac
Δ = 02-4·(-243)·(-8)
Δ = -7776
Delta is less than zero, so there is no solution for the equation

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